x^2=6x+(-6x+36)

Solution for x^2=6x+(-6x+36) equation:

x^2=6x+(-6x+36)

We move all terms to the left:

x^2-(6x+(-6x+36))=0


We calculate terms in parentheses: -(6x+(-6x+36)), so:

6x+(-6x+36)

We get rid of parentheses

6x-6x+36

We add all the numbers together, and all the variables

36

Back to the equation:

-(36)


a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*1}=\frac{-12}{2}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*1}=\frac{12}{2}
=6
$